If it's not what You are looking for type in the equation solver your own equation and let us solve it.
r^2+81-18r=0
a = 1; b = -18; c = +81;
Δ = b2-4ac
Δ = -182-4·1·81
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$r=\frac{-b}{2a}=\frac{18}{2}=9$
| 7b+8=5b-3+b+4 | | -r^2-81+18r=0 | | x+6=21+15=3x | | 0=r^2+81-18r | | 6v=5,280 | | 13p+4p+p-16p=12 | | 2m-m+3m=20 | | 6(x+3)=4x-1 | | 2m−m+3m=20 | | -3(4-2x)=6 | | 5x+6-3(x+1)=4x-6 | | 6(x-3)+x=4(2x+1)-22 | | 6-(1/3x)^2=-20 | | 8x+x-3x-3x-x=18 | | X-6y=3G | | q^2-4q+5=0 | | 6=z/45 | | 8x+x−3x−3x−x=18 | | q^2-4q-5=0 | | 3x-15+3=2x-10 | | -4x^2-6=90 | | 18m+2m+4m−2m−21m=16 | | -2+-3a=0 | | 8p/8=96p | | 0.75=n/3.6 | | 6(x+6)=4x- | | 2y-4×=8 | | 2m+5m+m-5m=9 | | 93=6x+5(-4x-15) | | q-q+2q=8 | | 10x(x)=390 | | y-y+5y=5 |